If `|x-1|>5,` then a. `x in (-4,6)` b. `x in [-4,6]` c. `x in (-oo,-4)uu(6,oo)` d. `x in (-oo,-4)uu[6,oo)`

If |x+2|lt=9 then x in (-7, 11) b. x in [-11 ,7] c. x in (-oo,7)uu(11 ,oo) d. x in (-oo,-7)uu[11 ,oo)

If x\ a n d\ a are real numbers such that a >0 and |x|> a , then (a) x in (-a ,oo) b. x in [-oo, a) c. x in (-a , a) d . x in (-oo,-a)U(a ,oo)

If |x+3|geq10 , then x in (-13 ,\ 7] b. x in (-oo,-13)uu(7,oo) c. x in (-13 ,7) d. x in (-oo,\ -13]uu[7,oo)

Solution set of the inequation (x^2+4x+4)/(2x^2-x-1)>0, is x in (-oo,-2)uu(-2,1) x in (-oo,-2)uu(-2,-1/2)uu(1,oo) x in (-oo,-2)uu(-1/2,1)uu(1,oo) x in (-oo,1)

Solution set of the inequation, (x^2-5x+6)/(x^2+x+1)<0 is x in (-oo,2) (b) x in (2,3) x in (-oo,2)uu(3,oo) (d) x in (3,oo)

The solution of system of linear inequalities in x represented on line as (i) x in ( - oo,-4) cup [3,oo) (ii) x in (- oo, -4] cup (5,oo) (iii) x in (- oo , -3) cup (5,oo) (iv) x in (-oo , -4) cup [ 5,oo)

Complete solution set of the inequation (x^2-1)(x^2-6x+8)geq0 is (a) x in [-1,1]uu[2,4] (b) x in (-oo,-1)uu[1,2]uu[4,oo] (c) x in [-1,2]uu[4,oo] (d) none of these

Match the column Column-I Column-II a. If ||x-1|-2|geq3, then x in p. [-2,-1]uu[5,6] b. If ||x-1|-2|lt=3,t h e nx in q. [-4,6] c. If 2 lt= |x-3|lt=3,t h e nx in r. (-oo,-4]uu[6,oo) d. If 2lt=||x-3|-1|lt=3,t h e nx in s. [0,1]uu[5,6]

If 1/(3x-4) lt 0 , then (i) x in (4/3 , oo) (ii) x in (-oo , 4/3) (iii) x in (0,oo) (iv) x in (0,4/3)

Let f(x)=sqrt(|x|-{x})(w h e r e{dot} denotes the fractional part of (x)a n dX , Y are its domain and range, respectively). Then (a) X in (-oo,1/2) and Y in (1/2,oo) (b) X in (-oo in ,1/2)uu[0,oo)a n dY in (1/2,oo) (c) X in (-oo,-1/2)uu[0,oo)a n dY in [0,oo) (d) none of these