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If 1lt=rlt=n , then \ n^(n-1)Cr 1 =(n-r+...

If `1lt=rlt=n ,` then `\ n^(n-1)C_r_ _1 =(n-r+1)\ ^n C_(r-1)dot`

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Let n\ a n d\ r be non negative integers such that 1lt=rlt=ndot Then, \ ^n C_r=n/rdot\ \ ^(n-1)C_(r-1)\ dot

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.^(n)C_(r)+2.^(n)C_(r-1)+.^(n)C_(r-2)=

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Let n\ a n d\ r be no negative integers suych that rlt=n .Then, \ ^n C_r+\ ^n C_(r-1)=\ ^(n+1)C_r

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