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Show that the product of perpendiculars on the line `x/a costheta+y/b sin theta=1` from the points `(+-sqrt(a^2-b^2), 0)i s b^2dot`

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Prove that the product of the lengths of the perpendiculars drawn from the points (sqrt(a^2-b^2),0) and (-sqrt(a^2-b^2),0) to the line x/a costheta + y/b sintheta=1 is b^2 .

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RD SHARMA ENGLISH-THE STRAIGHT LINES -All Questions
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