If the lines `3x-4y-7 = `0 and `2x-3y-5=0` are two diameters of a circle of area `49pi` square units, the equation of the circle is:

If the lines 2x-3y=5 and 3x-4y=7 are the diameters of a circle of area 154 square units, then obtain the equation of the circle.

If the lines 3x + y = 11 and x - y = 1 are the diameters of a circle of area 154 sq. units, then the equation of the circle is

The lines 2x-3y=5 and 3x-4y=7 are the diameters of a circle of area 154 sq. units. Then the equation of the circle is x^2+y^2+2x-2y=62 x^2+y^2+2x-2y=47 x^2+y^2-2x+2y=47 x^2+y^2-2x+2y=62

The lines 2x-3y=5 and 3x-4y=7 are diameters of a circle of are 154 sq. units. Taking pi=22/7 , show that the equation of the circle is x^(2)+y^(2)-2x+2y=47

If the lines x+y+3=0 and 2x-y-9=0 lie along diameters of a circle of circumference 8pi then the equation of the circle is :

If the lines 2x+3y+1=0 and 3x-y-4=0 lie along diameters of a circle of circumference 10 pi , then the equation of the circle is

If the lines 2x+3y+1=0 and 3x-y-4=0 lie along diameter of a circle of circumference 10pi , then show that the equation of the circle is x^(2)-y^(2)-2x+2y-23=0

If the lines 2x + 3y + 1 = 0 and 3x - y-4 = 0 lie along two diameters of a circle of circumference 10 pi , then the equation of circle is (i) x^(2) + y^(2) + 2x + 2y + 23 = 0 (ii) x^(2) + y^(2) - 2x - 2y - 23 = 0 (iii) x^(2) + y^(2) - 2 x + 2y - 23 = 0 (iv) x^(2) + y^(2) + 2x - 2y + 23 = 0

If the lines 3x-4y+4=0 and 6x-8y-7=0 are tangents to a circle, then find the radius of the circle.

If the lines 3x-4y+4=0 and 6x-8y-7=0 are tangents to a circle, then find the radius of the circle.