The line `2x -y +6= 0` meets the circle `x^2+y^2 -2y-9 =0` at A and B. Find the equation of the circle on AB as diameter.

The circle x^2+y^2=4 cuts the circle x^2+y^2+2x+3y-5=0 in A and B , Then the equation of the circle on AB as diameter is

If the straight line 2x+3y=1 intersects the circle x^2+y^2=4 at the points A and B then find the equation of the circle having AB as diameter.

If the circle x^2+y^2+2x+3y+1=0 cuts x^2+y^2+4x+3y+2=0 at A and B , then find the equation of the circle on A B as diameter.

If x+y=3 is the equation of the chord AB of the circle x^2+y^2-2x+4y-8=0 , find the equation of the circle having as diameter.

The intercept on the line y=x by the circle x^(2)+y^(2)-2x=0 is AB. Show that the equation of the circle with AB as diameter is x^(2)+y^(2)-x-y=0 .

The line x+3y=0 is a diameter of the circle x^2+y^2-6x+2y=0

The intercept on line y = x by circle x^2 + y^2- 2x = 0 is AB. Find equation of circle with AB as a diameter.

If the straight line represented by x cos alpha + y sin alpha = p intersect the circle x^2+y^2=a^2 at the points A and B , then show that the equation of the circle with AB as diameter is (x^2+y^2-a^2)-2p(xcos alpha+y sin alpha-p)=0

If y=2x is a chord of the circle x^2+y^2-10 x=0 , find the equation of a circle with this chord as diameter.

The abscissae of two points A and B are the roots of the equaiton x^2 + 2x-a^2 =0 and the ordinats are the roots of the equaiton y^2 + 4y-b^2 =0 . Find the equation of the circle with AB as its diameter. Also find the coordinates of the centre and the length of the radius of the circle.