Home
Class 11
MATHS
The equation of a circle with radius 5 a...

The equation of a circle with radius 5 and touching both the coordinate axes is `x^2+y^2+-10 x+-10 y+5=0` `x^2+y^2+-10 x+-10 y=0` `x^2+y^2+-10 x+-10 y+25=0` `x^2+y^2+-10 x+-10 y+51=0`

Answer

Step by step text solution for The equation of a circle with radius 5 and touching both the coordinate axes is x^2+y^2+-10 x+-10 y+5=0 x^2+y^2+-10 x+-10 y=0 x^2+y^2+-10 x+-10 y+25=0 x^2+y^2+-10 x+-10 y+51=0 by MATHS experts to help you in doubts & scoring excellent marks in Class 11 exams.

Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • STATISTICS

    RD SHARMA ENGLISH|Exercise All Questions|216 Videos
  • THE STRAIGHT LINES

    RD SHARMA ENGLISH|Exercise All Questions|493 Videos

Similar Questions

Explore conceptually related problems

The equation of the circle of radius 5 in the first quadrant which touches the x-axis and the line 3x-4y=0 is x^2+y^2-24 x-y-25=0 x^2+y^2-30 x-10 y+225=0 x^2+y^2-16 x-18 y-64=0 x^2+y^2-20 x-12 y+144=0

The equation of the parabola whose focus is (1,-1) and the directrix is x+y+7=0 is (a) x^2+y^2-2x y-18 x-10 y=0 (b) x^2+y^2-18 x-10 y-45=0 (c) x^2-18 x-10 y-45=0 (d) x^2+y^2-2x y-18 x-10 y-45=0

The centres of the three circles x^2 + y^2 - 10x + 9 = 0, x² + y^2 - 6x + 2y + 1 = 0, x^2 + y^2 - 9x - 4y +2=0

Find the centre and radius of the circle x^2+y^2+10 x-12 y+9=0

Find the angle between the circles given by the equations. x^2 + y^2 + 6x - 10y - 135 = 0, x^2 + y^2 - 4x+14y - 116 = 0

Find the centre and radius of the circle 3x^2 + 3y^2 - 8x - 10y + 3=0

The equation of the ellipse with focus (-1,1) directrix x-y+3=0 and eccentricity is a. 7x^2+2x y+7y^2+10 x+10 y+7=0 b. 7x^2+2x y+7y^2+10 x-10 y+7=0 c. 7x^2+2x y+7y^2+10 x-10 y+7=0 d. None of these

Find the centre and radius of the circles x^2+y^2-8x+10 y-12=0

Find the equation of circle passing through the origin and cutting the circles x^(2) + y^(2) -4x + 6y + 10 =0 and x^(2) + y^(2) + 12y + 6 =0 orthogonally.

Find the transverse common tangents of the circles x^(2) + y^(2) -4x -10y + 28 = 0 and x^(2) + y^(2) + 4x - 6y + 4= 0.