Equation of the hyperbola whose vertices...

Equation of the hyperbola whose vertices are `(+-3,0)` and foci at `(+-5,0)` is a.`16 x^2-9y^2=144` b. `9x^2-16 y^2=144` c. `25 x^2-9y^2=225` d. `9x^2-25 y^2=81`

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The equation of the hyperbola whose vertices are at (0, pm6) and eccentricity = (5)/(3) is (i) 16 x ^(2) - 9y^(2) = 576 (ii) 16y^(2)-9x^(2)=576 (iii) 9x^(2)-16y^(2)=576 (iv) 9y^(2)-16x^(2)=576

The equation of ellipse whose vertices are (pm 5, 0) and foci are (pm 4, 0) is (i) (x^(2))/(16)+(y^(2))/(9)=1 (ii) (x^(2))/(9)+(y^(2))/(16)=1 (iii) (x^(2))/(25)+(y^(2))/(9)=1 (iv) (x^(2))/(9)+(y^(2))/(25)=1

The equation of the chord of contact of tangents drawn from a point (2,-1) to the hyperbola 16x^(2)-9y^(2)=144 , is

The locus of the foot of the perpendicular from the center of the hyperbola x y=1 on a variable tangent is (a) (x^2+y^2)^2=4x y (b) (x^2-y^2)=1/9 (x^2-y^2)=7/(144) (d) (x^2-y^2)=1/(16)

The locus of the foot of the perpendicular from the center of the hyperbola x y=1 on a variable tangent is (a) (x^(2)+y^(2))^(2)=4xy (b) (x^2-y^2)=1/9 (c) (x^2-y^2)=7/(144) (d) (x^2-y^2)=1/(16)

The equation of the tangent to the hyperbola 16x^(2)-9y^(2)=144 at (5,8//3) , is

The locus of the foot of the perpendicular from the center of the hyperbola x y=1 on a variable tangent is (x^2+y^2)^2=4x y (b) (x^2-y^2)=1/9 (x^2-y^2)=7/(144) (d) (x^2-y^2)=1/(16)

Find the equations of the tangents drawn from the point (2, 3) to the ellipse 9x^2+16 y^2=144.

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