`R` is a relation from {11, 12, 13} to {8, 10, 12} defined by `y=x-3` . Then, `R^(-1)` is (a) {(8, 11), (10, 13)} (b) {(11, 8), (13, 10)} (c) {(10, 13), (8, 11), (8, 10)} (d) none of these

If R is a relation from set A={11 , 12 , 13} to set B={8, 10 , 12} defined by y=x-3, then write R^(-1)dot A. {(8,11),(10,13)} B. {(8,11),(10,12)} C. {(10,13),(10,11)} D. none of these

the median of 10, 14, 11, 9, 8, 12, 6 is

Evaluate: = |(10 !, 11 !, 12 !), (11 !, 12 !, 13 !), (12 !, 13 !, 14 !)|

Find the inverse relation R^(-1) in the following case: R is a relation from {11 , 12 , 13}to\ {8, 10 , 12} defined by y=x-3.

Let f a n d g be two functions given by f={(2,4), (5,6), (8,-1), (10 ,-3)} a n d g={(2,5), (7,1),(8,4),(10 , 13),(11,-5)}. Find the Domain of f + g

Mean deviation from the mean for data 6, 7 10, 12, 13, 4, 8, 12 is

Choose the correct option (-5)/(13)+?=-1 (a) 8/(13) (b) (-8)/(13) (c)(-18)/(13) (d) (18)/(13)

The point on the line 3x-2y=1 which is closest to the origin is (A) (3/13, - 2/13) (B) (5/11, 2/11) (C) (3/5, 2/5) (D) none of these

The value of |(11,12,13),(12,13,14),(13,14,15)| , is

Two circles, each having radius 4, have a common tangent given by 3x+2y-6=0 at (2, 0) . Then their centres are : (A) (2+ 5/sqrt(13), 8/sqrt(13)), (2- 5/sqrt(13) , (-8)/sqrt(13)) (B) (2+ 12/sqrt(13), 8/sqrt(13)) , (2- 12/sqrt(13), (-8)/sqrt(13)) (C) (2, 3), (4, 5) (D) none of these