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Let f: Nuu{0}->Nuu{0} be defined by f(n)...

Let `f: Nuu{0}->Nuu{0}` be defined by `f(n)={n+1,\ if\ n\ i s\ even\,\ \ \n-1,\ if\ n\ i s\ od d` Show that `f` is invertible and `f=f^(-1)` .

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