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The function `f: A->B` defined by `f(x)=-x^2+6x-8` is a bijection, if `A=(-oo,\ 3]` and `B=(-oo,\ 1]` (b) `A=[-3,\ oo)` and `B=(-oo,\ 1]` (c) `A=(-oo,\ 3]` and `B=[1,\ oo)` (d) `A=[3,\ oo)` and `B=[1,\ oo)`

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RD SHARMA ENGLISH-FUNCTION-All Questions
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  3. The function f: A->B defined by f(x)=-x^2+6x-8 is a bijection, if A=(-...

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