The function `f: R->R` , `f(x)=x^2` is (a) injective but not surjective (b) surjective but not injective (c) injective as well as surjective (d) neither injective nor surjective

Let S be the set of all triangles and R^+ be the set of positive real numbers. Then the function f: SrarrR^+,f(Delta)=area of Delta ,where Delta in S , is injective but not surjective. surjective but not injective injective as well as surjective neither injective nor surjective

Let R be the set of real numbers. If f:R->R is a function defined by f(x)=x^2, then f is injective but not surjective surjective but not injective bijective none of these (a) injective but not surjective (b) surjective but not injective (c) bijective (d) non of these

Let f:[-oo,0)->(1,oo) be defined as f(x)=(1+sqrt(-x))-(sqrt(-x)-x) then f(x) is (A) injective but not surjective (B) injective as well as surjective (C) neither injective nor surjective (D) surjective nut not injective

Let A{x :-1lt=xlt=1}a n df: Avec such that f(x)=x|x|, then f is (a) bijection (b) injective but not surjective (c)Surjective but not injective (d) neither injective nor surjective

Let A}x :-1lt=xlt=1}a n df: Avec A such that f(x)=x|x|, then f is (a) bijection (b) injective but not surjective Surjective but not injective (d) neither injective nor surjective

f: R->R given by f(x)=x+sqrt(x^2) is (a) injective (b) surjective (c) bijective (d) none of these

Let f:N to Z and f (x)=[{:((x-1)/(2),"when x is odd"),(-(x)/(2),"when x is even"):}, then: (a). f (x) is bijective (b).f (x) is injective but not surjective (c).f (x) is not injective but surjective (d).f (x) is neither injective nor subjective

Let A={x in R :-1lt=xlt=1}=B . Then, the mapping f: A->B given by f(x)=x|x| is (a) injective but not surjective (b) surjective but not injective (c) bijective (d) none of these

Let A={x in R :-1lt=xlt=1}=B . Then, the mapping f: A->B given by f(x)=x|x| is (a) injective but not surjective (b) surjective but not injective (c) bijective (d) none of these

Show that the function f: R->R given by f(x)=x^3 is injective.