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Let f: R-{3/5}->R be defined by f(x)=(3x...

Let `f: R-{3/5}->R` be defined by `f(x)=(3x+2)/(5x-3)` . Then (a).f^-1(x)=f(x). (b).f-1(x)= -f(x). (c). (fof)=x (d). f-1(x)=(1/19)f(x)

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