Evaluate : `cos(2cos^(-1)x+sin^(-1)x)  a t x=1/5`

Explanation

To evaluate the expression \( \cos(2\cos^{-1}x + \sin^{-1}x) \) at \( x = \frac{1}{5} \), we can follow these steps:

### Step 1: Rewrite the expression
We start with the expression:
\[ \cos(2\cos^{-1}x + \sin^{-1}x) \]
Using the identity \( \sin^{-1}x + \cos^{-1}x = \frac{\pi}{2} \), we can rewrite \( \sin^{-1}x \) as:
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