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If (tan^(-1) x)^2 + (cot^(-1) x)^2 = (5p...

If `(tan^(-1) x)^2 + (cot^(-1) x)^2 = (5pi^2)/8` then `x` equals

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To solve the equation \((\tan^{-1} x)^2 + (\cot^{-1} x)^2 = \frac{5\pi^2}{8}\), we can follow these steps: ### Step 1: Use the identity for cotangent inverse We know that: \[ \cot^{-1} x = \frac{\pi}{2} - \tan^{-1} x \] Substituting this into the equation gives: ...
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