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solve:sin^-1x+sin^-1 2x=pi/3...

solve`:sin^-1x+sin^-1 2x=pi/3`

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To solve the equation \( \sin^{-1} x + \sin^{-1} 2x = \frac{\pi}{3} \), we can follow these steps: ### Step 1: Isolate one of the inverse sine terms We start by isolating \( \sin^{-1} 2x \): \[ \sin^{-1} 2x = \frac{\pi}{3} - \sin^{-1} x \] ...
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