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If [(1,-tantheta),(tantheta,1)][(1,tanth...

If `[(1,-tantheta),(tantheta,1)][(1,tantheta),(-tantheta,1)]^(-1)=[(a,-b),(b, a)]` , then `a=1,\ \ b=0` (b) `a=cos2\ theta,\ \ b=sin2\ theta` (c) `a=sin2\ theta,\ \ b=cos2theta` (d) none of these

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If |(1,-t a ntheta),(t a ntheta,1)| |(1,t a ntheta),(-t a ntheta,1)|^-1=|[a,-b],[b ,a]| , then a. a=cos2theta b. a=1 c. b=sin2theta d. b=-1

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