If a triangle ABC, inscribed in a fixed circle, be slightly varied in such away as to have its vertices always on the circle, then show that `(d a)/(c a sA)+(d b)/(cosB)+(d c)/(cosC)=0.`

If in a triangle A B C , the side c and the angle C remain constant, while the remaining elements are changed slightly, using differentials show that (d a)/(c sA)+(d b)/(cosB)=0

If in a triangle A B C , the side c and the angle C remain constant, while the remaining elements are changed slightly, using differentials show that (d a)/(c sA)+(d b)/(cosB)=0

If a circle is inscribed in right angled triangle ABC with right angle at B, show that the diameter of the circle is equal to AB+BC-AC.

A variable triangle A B C is circumscribed about a fixed circle of unit radius. Side B C always touches the circle at D and has fixed direction. If B and C vary in such a way that (BD) (CD)=2, then locus of vertex A will be a straight line. (a)parallel to side BC (b)perpendicular to side BC (c)making an angle (pi/6) with BC (d) making an angle sin^(-1)(2/3) with B C

A variable triangle ABC is circumscribed about a fixed circle of unit radius. Side BC always touches the circle at D and has fixed direction. If B and C vary in such a way that (BD). (CD)=2, then locus of vertex A will be a straight line

If A is the area and C is the circumference of a circle, then its radius is (a) A/C (b) (2A)/C (c) (3A)/C (d) (4A)/C

If in a triangle A B C , the side c and the angle C remain constant, while the remaining elements are changed slightly, show that (d a)/(cosA)+(d b)/(cosB)=0.

If in a triangle ABC, (cosA)/a=(cosB)/b=(cosC)/c ,then the triangle is

Let a and b represent the lengths of a right triangles legs. If d is the diameter of a circle inscribed into the triangle, and D is the diameter of a circle circumscribed on the triangle, the d+D equals. (a) a+b (b) 2(a+b) (c) 1/2(a+b) (d) sqrt(a^2+b^2)

In any triangle ABC, if a=18 , b=24 , c=30 , findcosA, cosB, cosC