Find the approximate value of `f(2. 01)` , where `f(x)=4x^2+5x+2` .

Explanation

To find the approximate value of \( f(2.01) \) where \( f(x) = 4x^2 + 5x + 2 \), we will use the concept of differentials.

### Step 1: Differentiate the function
First, we need to find the derivative of the function \( f(x) \).

\[ f'(x) = \frac{d}{dx}(4x^2 + 5x + 2) = 8x + 5 \]
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