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Find the equation of the tangent and normal to the parabola `y^2=4a x` at the point `(a t^2,\ 2a t)` .

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Given equation of parabola is `y^2=4ax`
Differentiating w,r,t `x` we get
`2y dy/dx=4a`
`=>dy/dx=(2a)/y`
...
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