The angle of intersection of the curves `x y=a^2` and `x^2-y^2=2a^2` is
(a)`0^o`
(b) `45^o`
(c) `90^o`
(d) `30^o`

Find the angle of intersection of curve x^2+y^2-4x-1=0 and x^2+y^2-2y-9=0

Find the angle of intersection of the following curves : y^2=x \ a n d \ x^2=y

The angle of intersection between the curves, y=x^2 and y^2 = 4x , at the point (0, 0) is (A) pi/2 (B) 0 (C) pi (D) none of these

The angle between the curves y^2=x and x^2=y at (1,\ 1) is tan^(-1)4/3 (b) tan^(-1)3/4 (c) 90 (d) 45

The locus of the point of intersection of the tangent to the circle x^(2)+y^2=a^2 ,which include an angle of 45 is the curve (x^2+y^2)^2 = λ(a^2)(x^2+y^2-a^2) . the value of lambda(λ) is : (a) 2 (b) 4 (c)8 (d) 16

Let C be a curve which is the locus of the point of intersection of lines x=2+m and m y=4-mdot A circle s-=(x-2)^2+(y+1)^2=25 intersects the curve C at four points: P ,Q ,R ,a n dS . If O is center of the curve C , then O P^2+O P^2+O R^2+O S^2 is (a) 50 (b) 100 (c) 25 (d) (25)/2

In an isosceles triangle A B C if A C=B C and A B^2=2A C^2 , then /_C= 30o (b) 45o (c) 90o (d) 60o

Two equal circles touch each other externally at C and A B is a common tangent to the circles. Then, /_A C B= 60o (b) 45o (c) 30o (d) 90o

Let B and C are the points of intersection of the parabola x=y^(2) and the circle y^(2)+(x-2)^(2)=8 . The perimeter (in units) of the triangle OBC, where O is the origin, is

The diagonals of a parallelogram A B C D intersect at O . If /_B O C=90^0\ a n d\ /_B D C=50^0, then /_O A B= (a) 40^0 (b) 50^0 (c) 10^0 (d) 90^0