A beam is supported at the two ends and is uniformly loaded. The bending moment `M` at a distance `x` from one end is given by `M=(W x)/3-W/3(x^3)/(L^2)` . Find the point at which `M` is maximum.

A beam is supported at the two ends and is uniformly loaded. The bending moment M at a distance x from one end is given by M=(W L)/2x-W/2x^2 M=(W x)/3-W/3(x^3)/(L^2) Find the point at which M is maximum in each case.

A beam is supported at the two ends and is uniformly loaded. The bending moment M at a distance x from one end is given by M=(W L)/2x-W/2x^2 . Find the point at which M is maximum.

A beam is supported at the two ends and is uniformly loaded. The bending moment M at a distance x from one end is given by (i) M=(W L)/2x-W/2x^2 (ii) M=(W x)/3-W/3(x^3)/(L^2) Find the point at which M is maximum in each case.

The electric foield at a point A on the perpendicular bisector of a uniformly charged wire of length l=3m and total charge q = 5 nC is x V/m. The distance of A from the centre of the wire is b = 2m. Find the value of x.

A mass m is at a distance a from one end of a uniform rod of length l and mass M. Find the gravitational force on the mass due to tke rod.

A mass m is at a distance a from one end of a uniform rod of length l and mass M. Find the gravitational force on the mass due to the rod.

A diving board 3.00 m long is supported at a point 1.00 m from the end and a diver weighing 500 N stands at the free end. The diving board is of uniform cross section and weighs 280 N . Find. The force at the support point

A beam of weight W supports a block of weight W . The length of the beam is L . and weight is at a distance L/4 from the left end of the beam. The beam rests on two rigid supports at its ends. Find the reactions of the supports.

A string of length 'L' is fixed at both ends . It is vibrating in its 3rd overtone with maximum amplitude 'a'. The amplitude at a distance L//3 from one end is

A stationary wave of amplitude A is generated between the two fixed ends x = 0 and x = L. The particle at x=(L)/(3) is a node. There are only two particle between x =(L)/(6) and x=(L)/(3) which have maximum speed half of the maximum speed of the anti-node. Again there are only two particles between x= 0 and x=(L)/(6) which have maximum speed half of that at the antibodes. The slope of the wave function at x=(L)/(3) changes with respect to time according to the graph shown. The symbols mu, omega and A are having their usual meanings if used in calculations. The time period of oscillations of a particle is