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Evaluate: int(cos2x-cos2alpha)/(cosx-cos...

Evaluate: `int(cos2x-cos2alpha)/(cosx-cosalpha)\ dx`

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To evaluate the integral \[ I = \int \frac{\cos(2x) - \cos(2\alpha)}{\cos(x) - \cos(\alpha)} \, dx, \] we can follow these steps: ...
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