Evaluate: `int1/(sin(x-a)cos(x-b))\ dx`

Explanation

To evaluate the integral \( \int \frac{1}{\sin(x-a) \cos(x-b)} \, dx \), we can follow these steps:

### Step 1: Multiply by a suitable expression
We start by multiplying the numerator and denominator by \( \cos(a-b) \):

\[ \int \frac{1}{\sin(x-a) \cos(x-b)} \, dx = \int \frac{\cos(a-b)}{\sin(x-a) \cos(x-b) \cos(a-b)} \, dx \]
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