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"F i n d"int[log(logx)+1/((logx)^2)]dx...

`"F i n d"int[log(logx)+1/((logx)^2)]dx`

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To solve the integral \( I = \int \left( \log(\log x) + \frac{1}{(\log x)^2} \right) dx \), we can break it down into two separate integrals: 1. \( I_1 = \int \log(\log x) \, dx \) 2. \( I_2 = \int \frac{1}{(\log x)^2} \, dx \) Thus, we have: \[ I = I_1 + I_2 ...
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