`int e^x ((1-sinx)/(1-cosx)) dx=` (A) ` e^xtan(x/2)+C` (B) ` e^xcot(x/2)+C` (C) `-1/2 e^xtan(x/2)+C` (D) `-1/2 e^xcot(x/2)+C`

int(e^(-x/2)sqrt(1-sinx))/(1+cosx)dx

int(e^x)/((1+e^x)(2+e^x))dx

Choose the correct answer intx^2e^(x^3)dx equals(A) 1/3e^(x^3) +C (B) 1/3e^(x^2)+C (C) 1/2e^(x^3)+C (D) 1/2e^(x^2)+C

int(e^x(1+x))/(cos^2(x e^x))\ dx= (a) 2(log)_ecos(x e^x)+C (b) sec(x e^x)+C (c) tan(x e^x)+C (d) tan(x+e^x)+C

int( x-1)e^(-x) dx is equal to : a) ( x- 2)e^(x) + C b) x e^(-x) + C c) - x e^(x) + C d) ( x+1)e^(-x) +C

The integral inte^x(f(x)+f\'(x))dx can be solved by using integration by parts such that: I=inte^xf(x)dx+inte^xf\'(x)dx=e^xf(x)-inte^xf\'(x)dx+inte^xf\'(x)dx=e^xf(x)+C , and inte^(ax)(f(x)+(f\'(x))/a)dx=e^(ax)f(x)/a+C ,Now answer the question: int(e^x(2-x^2))/((1-x)sqrt(1-x^2))dx (A) e^xsqrt((1-x)/(1+x))+C (B) e^xsqrt((1+x)/(1-x))+C (C) e^xsqrt((2-x)/(2+x))+C (D) none of these

Evaluate: int(cos e c^2x)/(1+cotx)dx

int(x+3)/((x+4)^2)e^x\ dx= a. (e^x)/(x+4)+C (b) (e^x)/(x+3)+C (c) 1/((x+4)^2)+C (d) (e^x)/((x+4)^2)+C

int(e^x(1+x))/(cos^2 (e^x * x) )dx equals(A) -cot(e x^x)+C (B) tan(x e^x)+C (C) tan(e^x)+C (D) cot(e^x)+C

inte^x(1-cotx+cot^2x)dx= e^xcotx+C (b) e^xcotx+C (c) e^x\ cos e c\ x+C (d) e^x\ cos e c\ x+C