If `| vec axx vec b|=4,\ vec adot vec b =2,\ t h e n\ | vec a|^2| vec b|^2=` `6` b. `2` c. `20` d. 8

If | vec axx vec b|^2=( vec adot vec b)^2=144\ a n d\ | vec a|=4 , find vec bdot

If | vec a|=13 ,\ | vec b|=5\ a n d\ vec adot vec b=60 , t h e n find | vec axx vec b|dot

Find | vec a- vec b|,\ if:| vec a|=2,\ | vec b|=5\ a n d\ vec adot vec b=8

Find | vec a- vec b|,\ if:| vec a|=2,\ | vec b|=3\ a n d\ vec adot vec b=4

Find | vec a- vec b|,\ if:| vec a|=3,\ | vec b|=4\ a n d\ vec adot vec b=1

If | vec a|=2,\ | vec b|=5\ a n d\ | vec axx vec b|=8,\ find veca.vecb

If vec r. vec a=0, vec r. vec b=1 \ and \ [[ vec r ,vec a, vec b]]=1, vec adot vec b!=0,( vec adot vec b)^2-| vec a|^2| vec b|^2=-1, then find vec r in terms of vec a \ and \ vec b .

For any two vectors vec a and vec b , prove that: | vec a+ vec b|^2=| vec a|^2+| vec b|^2+2 vec adot vec b , | vec a- vec b|^2=| vec a|^2+| vec b|^2-2 vec adot vec b , | vec a+ vec b|^2+| vec a- vec b|^2=2(| vec a|^2+| vec b|^2) and | vec a+ vec b|^2=| vec a- vec b|^2 iff vec a_|_ vec bdot Interpret the result geometrically.

The value of (axxb)^2 is | vec a|^2+| vec b|^2-( vec adot vec b)^2 b. | vec a|^2| vec b|^2-( vec adot vec b)^2 c. | vec a|^2+| vec b|^2-2( vec adot vec b)^2 d. | vec a|^2+| vec b|^2- vec adot vec b

If | vec a|=2| vec b|=5 and | vec axx vec b|=8, then find the value of vec a . vec bdot