A fair die is thrown 20 times. The probability that on the 10th throw, the fourth six appears is `^20 C_(10)xx5^6//6^(20)` b. `120xx5^7//6^(10)` c. `84xx5^6//6^(10)` d. none of these

A fair die is thrown 20 times. The probability that on the 10th throw, the fourth six appears is a. "^20 C_(10)xx5^6//6^(20) b. 120xx5^7//6^(10) c. 84xx5^6//6^(10) d. none of these

A fair die is tossed eight times. The probability that a third six is observed in eight throw is (\ ^7C_(10)xx5^7)/(6^7) b. (\ ^7C_2xx5^2)/(6^8) c. (\ ^7C_2xx5^5)/(6^6) d. none of these

Four die are thrown simultaneously. The probability that 4 and 3 appear on two of the die given that 5 and 6 have appeared on other two die is a) 1/6 b) 1/36 c) 12/151 d) none of these

The sum of 20 terms of a series of which every even term is 2 times the term before it, every odd term is 3 times the term before it, the first term being unity is a. (2/7)(6^(10)-1) b. (3/7)(6^(10)-1) c. (3/5)(6^(10)-1) d. none of these

A die is thrown three times, find the probability that 4 appears on the third toss if it is given that 6 and 5 appear respectively on first two tosses.

A die is thrown three times, find the probability that 4 appears on the third toss if it is given that 6 and 5 appear respectively on first two tosses.

A bag contains 20 coins. If the probability that the bag contains exactly 4 biased coin is 3/4 and that of exactly 5 biased coin is 2/3, then the probability that all the biased coin are sorted out from bag is exactly 10 draws is 5/(10)(^(16)C_6)/(^(20)C_9)+1/(11)(^(15)C_5)/(^(20)C_9) b. 2/(33)[(^(16)C_6+5^(15)C_5)/(^(20)C_9)] c. 5/(33)(^(16)C_7)/(^(20)C_9)+1/(11)(^(15)C_6)/(^(20)C_9) d. none of these

A person predicts the outcome of 20 cricket matches of his home team. Each match can result in either a win, loss, or tie for the home team. Total number of ways in which he can make the predictions so that exactly 10 predictions are correct is equal to a. ^20 C_(10)xx2^(10) b. ^20 C_(10)xx3^(20) c. ^20 C_(10)xx3^(10) d. ^20 C_(10)xx2^(20)

A die is thrown 560 times. The number 6 appears on the upper face 72 times. A die is thrown at random. What is the probability of getting 6.

Perform the following calculations to the appropriate number of signficiant digits (6.02xx10^(23)xx4.00)/(4.0xx10^(20))