`[{(-1/3)^2}^(-2)]^(-1)` =
(a) `1/(81)` (b) `1/9` (c) `-1/(81)` (d) `-1/9`

9xx(-1/3)xx(-3)xx(-1/9)= (a) 1 (b) -1 (c) -3 (d) 3

The sum of the series 2/3+8/9+(26)/(27)+(80)/(81)+ to n terms is (a) n-1/2(3^(-n)-1) (b) n-1/2(1-3^(-n)) (c) n+1/2(3^n-1) (d) n-1/2(3^n-1)

When simplified (-1/(27))^(-2/3) is (a) 9 (b) -9 (c) 1/9 (d) -1/9

(1)/(3)-(1)/(2).(1)/(9)+(1)/(3).(1)/(27)-(1)/(4).(1)/(81)+….oo=

The coordinates of the point on the ellipse 16x^2 +9y^2 =400 where the ordinate decreases at the same rate at which the abscissa increases, are (a) (3,3/16) and (-3,-3/16) (b) (3,-16/3) and (-3,16/3) (c) (1/16,1/9) and (-1/16,-1/9) (d) (1/16,-1/9) and (-1/16,1/9)

If (2/3)^x\ \ (3/2)^(2x)=(81)/(16), . then x= (a) 2 (b) 3 (c) 4 (d) 1

-(2)/(3)-(1)/(2)((4)/(9))-(1)/(3)((8)/(27))-(1)/(4)((16)/(81))-…..oo=

int(dx)/(sqrt(9x-4x^2)) equals(A) 1/9sin^(-1)((9x-8)/8)+C (B) 1/2sin^(-1)((8x-9)/9)+C (C) 1/3sin^(-1)((9x-8)/8)+C (D) 1/2sin^(-1)((9x-8)/9)+C

If int sqrt(1-x^2)/x^4dx=A(x).(sqrt(1-x^2))^m where A(x) is a function of x then (A(x))^m = (A) -1/(27x^9) (B) 1/(27x)^9 (C) 1/(3x^9) (D) -1/(3x^9)

If the first term of a G.P is 27 and 8th term is 1/81 , then the sum of its first 10 terms is (i) 27/2(1-1/(3^(10))) (ii) 81/2(1/(3^(10))-1) (iii) 27/2(1/(3^(10))-1) (iv) 81/2(1-1/(3^(10)))