The sum of the coefficients in the monomials `3a^2b` and `-2a b^2` is

Options

A. 5
B. -1
C. 1
D. -6

Answer

To find the sum of the coefficients in the monomials \(3a^2b\) and \(-2ab^2\), we will follow these steps:

### Step 1: Identify the coefficients
The coefficients in the given monomials are the numerical parts that multiply the variables.

- For the monomial \(3a^2b\), the coefficient is **3**.
- For the monomial \(-2ab^2\), the coefficient is **-2**.

### Step 2: Write down the coefficients
We have:
- Coefficient of \(3a^2b\) = **3**
- Coefficient of \(-2ab^2\) = **-2**

### Step 3: Calculate the sum of the coefficients
Now, we will add the coefficients together:
\[ \text{Sum} = 3 + (-2) \]

### Step 4: Simplify the expression
Adding the coefficients:
\[ 3 + (-2) = 3 - 2 = 1 \]

### Final Answer
The sum of the coefficients in the monomials \(3a^2b\) and \(-2ab^2\) is **1**.

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