The ratio of the area and circumference of a circle of diameter `d` is
(a)`d`
(b) `d/2`
(c)`d/4`
(d) `2\ d`

The ratio of the perimeter (circumference) and diameter of a circle is (a) pi\ (b) 2pi (c) pi/2 (d) pi/4

If A is the area and C is the circumference of a circle, then its radius is (a) A/C (b) (2A)/C (c) (3A)/C (d) (4A)/C

Recall, pi is defined as the ratio of the circumference (say c) of a circle to its diameter (say d). That is, pi=c/d . This seems to contradict the fact the pi is irrational How will you resolve this contradiction?

The length of the diagonal of a square is d units. The area of the square is (a) d^2 (b) 1/2d^2 (c) 1/4d^2 (d) 2d^2

If the circumference and the area of a circle are numerically equal, then diameter of the circle is (a) pi/2 (b) 2pi (c) 2 (d) 4

The radii of two circles are in the ratio 2: 3. The ratio of their areas is (a) 2:3 (b) 4:9 (c) 3:2 (d) 9:4

The circumferences of two circles are in the ratio 3: 4. The ratio of their areas is (a) 3:4 (b) 4:3 (c)9:16 (d) 16 :9

Let a and b represent the lengths of a right triangles legs. If d is the diameter of a circle inscribed into the triangle, and D is the diameter of a circle circumscribed on the triangle, the d+D equals. (a) a+b (b) 2(a+b) (c) 1/2(a+b) (d) sqrt(a^2+b^2)

A line meets the coordinate axes at A and B . A circle is circumscribed about the triangle O A Bdot If d_1a n dd_2 are distances of the tangents to the circle at the origin O from the points Aa n dB , respectively, then the diameter of the circle is (a) (2d_1+d_2)/2 (b) (d_1+2d_2)/2 (c) d_1+d_2 (d) (d_1d_2)/(d_1+d_2)

The areas of two circles are in the ratio 49 : 36. The ratio of their circumference is (a) 7:6 (b) 6:7 (c) 3:2 (d) 2:3