A bag contains 4 green balls, 4 red balls and 2 blue balls. If a ball is drawn from the bag, the probability of getting neither green nor red ball is :

Options

A. `2/5`
B. `1/2`
C. `4/5`
D. `1/5`

Answer

To find the probability of drawing neither a green nor a red ball from the bag, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the total number of balls in the bag**:
- The bag contains:
- 4 green balls
- 4 red balls
- 2 blue balls
- Total number of balls = 4 (green) + 4 (red) + 2 (blue) = 10 balls.

2. **Determine the favorable outcomes**:
- We need to find the probability of getting neither a green nor a red ball. This means we are looking for the blue balls.
- The number of blue balls in the bag = 2.

3. **Use the probability formula**:
- The probability of an event is given by the formula:
\[ \text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \]
- Here, the number of favorable outcomes (blue balls) = 2, and the total number of outcomes (total balls) = 10.

4. **Calculate the probability**:
- Substitute the values into the formula:
\[ \text{Probability of getting neither green nor red} = \frac{2}{10} \]
- Simplifying this fraction:
\[ \frac{2}{10} = \frac{1}{5} \]

5. **Conclusion**:
- Therefore, the probability of drawing neither a green nor a red ball is \(\frac{1}{5}\).