Let `n` be a natural number. If the division `n-:2` leaves no remainder, what might be the unites digit of `n` ?

Let n be a natural number. If the division n -:2 leaves a remaineder of 1, what might be the units digit of n ?

Let n be a natural number such that the division n-:5 leaves a remainder of 4, and the division n-:2 leaves a remainder of 1. What must be the units digit of n ?

If the division of a natural number n by 5 leaves a remainder of 3, what might be the ones digit of n?

If n is a natural number, then sqrt(n) is:

If A_(n)=7^(n)-1 , what is the units digit of A_(33) ?

If S_(n) = (4^n) + 3 , what is the units digit of S_(100) ?

Consider the numbers 4^n , where n is a natural number. Cheek whether there is any value of n for which 4^n ends with the digit zero.

Let N be the number of 4- digit numbers which contain not more than 2 different digits. The sum of the digits of N is :

Let a_(n) denote the number of all n-digit numbers formed by the digits 0,1 or both such that no consecutive digits in them are 0. Let b_(n) be the number of such n-digit integers ending with digit 1 and let c_(n) be the number of such n-digit integers ending with digit 0. Which of the following is correct ?

Let a_(n) denote the number of all n-digit numbers formed by the digits 0,1 or both such that no consecutive digits in them are 0. Let b_(n) be the number of such n-digit integers ending with digit 1 and let c_(n) be the number of such n-digit integers ending with digit 0. Which of the following is correct ?