Subtract the sum of `3l-4m-7n^2a n d\ 2l+3m-4n^2` from the sum of `9l+2m-3n^2` and `-3l+m+4n^2dot`

Subtract: 3l\ (l-4m+5n) from 4l(10 n-3m+2l)

Simplify: 2m-3n+5p+2m+n-2p-3m-4n+p

the acute angle between two lines such that the direction cosines l, m, n of each of them satisfy the equations l + m + n = 0 and l^2 + m^2 - n^2 = 0 is

Find the angle between the lines whose direction cosine are given by the equation: "l"+2"m"+3"n"=0" and "3"l m"-4"ln"+"m n"=0

If l ,\ m,\n are three lines such that l || m\ a n d\ n_|_l , prove that n_|_mdot

The product of (3m^2n^7(-4m^4n^3) is equivalent to :

The set of quantum numbers, n = 2, l = 2, m_(l) = 0 :

The eqautions of lines L_(1) and L_(2) are y=mx and y=nx , respectively. Suppose L_(1) makes twice as large an angle with the horizontal (measured counterclockwise from the positive x - axis) as does L_(2) and m = 4n, then the value of ((m^(2)+4n^(2)))/((m^(2)-6n^(2))) is equal to (where, n ne 0 )

If m is the A.M. of two distinct real numbers l and n""(""l ,""n"">""1) and G1, G2 and G3 are three geometric means between l and n, then G1 4+2G2 4+G3 4 equals, (1) 4l^2 mn (2) 4l^m^2 mn (3) 4l m n^2 (4) 4l^2m^2n^2

The set of quantum numbers, n = 3, l = 2, m_(l) = 0