Show that the product of the areas of the floor and two adjacent walls of a cuboid is the square of its volume.

The length of a hall is 18m and the width 12m. The sum of the areas of the floor and the flat roof is equal to the sum of the areas of the four walls. Find the height of the hall.

The length of a hall is 18m and the width 12m. The sum of the areas of the floor and the flat roof is equal to the sum of the areas of the four walls. Find the height of the hall.

The length of a hall is 20\ m and width 16\ mdot The sum of the area of the floor and the flat roof is equal to the sum of the areas of the four walls. Find the height and the volume of the hall.

The length of a hall is 20m and width 16m . The sum of the areas of the floor and the flat roof is equal to the sum of the areas of the four walls. Find the height and the volume of the hall.

The length of a hall is 20\ m and width 16\ mdot The sum of the area of the floor and the flat roof is equal to the sum of the areas of the four walls. Find the height and the volume of the hall.

Prove that in any parallelogram the sum of squares of the diagonals is twice the sum of the squares of two adjascent sides. Also show that the difference of the squares on two adjacent sides is equal to the rectangle contained by either diagonal and the projection of the other upon it.

A room (cubical) is made of mirros. An insect is moving along the diagonal on the floor such that the velocity of image of insect on two adjacent wall mirrors is 10(cm)/(sec) . The velocity of image of insect in ceiling mirror is

The volume of a cuboid is given by the product of its length, breadth and height. The length of a cuboid is 3 times its breadth and the height is one-half of the length. Find its volume if breadth is b\ c mdot

Show that the area of the triangle whose two adjacent sides are determined by the vectors veca=3hati+4hatj, vecb=-5hati+7hatj is 20 1/2 square units.

A cuboid has total surface area of the 40\ m^2 and its lateral surface area is 26\ m^2 . Find the area of its base.