The vectors `vecA` has a magnitude of 5 unit `vecB` has a magnitude of 6 unit and the cross product of `vecA and vecB` has a magnitude of 15 unit. Find the angle between `vecA and vecB`.

Explanation

To find the angle between the vectors \(\vec{A}\) and \(\vec{B}\), we can use the formula for the magnitude of the cross product of two vectors:

\[ |\vec{A} \times \vec{B}| = |\vec{A}| \cdot |\vec{B}| \cdot \sin \theta \]

### Step 1: Write down the known values
We know:
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