Can you have `vecAxxvecB=vecA.vecB` with `A!=0 and B!=0?` What if one of the two vectors is zero?

Assertion : The direction of a zero (null) vector is indeteminate. Reason : We can have vecAxx vecB = vecA *vecB with vecA ne vec0 and vecB ne vec0 .

A solution of the vector equation vecrxxvecb=vecaxxvecb , where veca, vecb are two given vectors is where lamda is a parameter.

Given that veca.vecb=0 and veca xx vecb=0 . What can you conclude about the vectors veca and vecb .

If vecAxxvecB=vecC , then choose the incorrect option : [ vecA and vecB are non zero vectors]

If two out to the three vectors , veca, vecb , vecc are unit vectors such that veca + vecb + vecc =0 and 2(veca.vecb + vecb .vecc + vecc.veca) +3=0 then the length of the third vector is

Let veca,vecb and vecc be non-zero vectors such that no two are collinear and (vecaxxvecb)xxvecc=1/3|vecb||vecc|veca If theta is the acute angle between the vectors vecb and vecc then sin theta equals

If veca, vecb and vecc are non - zero vectors such that veca.vecb= veca.vecc ,then find the goemetrical relation between the vectors.

If vecx.veca=0vecx.vecb=0 and vecx.vecc=0 for some non zero vector vecx then show that [veca vecb vecc]=0

If vecx.veca=0vecx.vecb=0 and vecx.vecc=0 for some non zero vector vecx then show that [veca vecb vecc]=0

If veca and vecb are two vectors, such that veca.vecblt0 and |veca.vecb|=|vecaxxvecb| then the angle between the vectors veca and vecb is (a) pi (b) (7pi)/4 (c) pi/4 (d) (3pi)/4