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A ball is thrown up at a speed of 4.0 m/...

A ball is thrown up at a speed of 4.0 m/s. Find the maximum height reached by the ball. Take `g=10 m//s^2`.

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To find the maximum height reached by a ball thrown upward at a speed of 4.0 m/s, we can use the kinematic equation: \[ v^2 = u^2 + 2as \] where: - \( v \) is the final velocity (0 m/s at maximum height), - \( u \) is the initial velocity (4.0 m/s), - \( a \) is the acceleration (which will be -g, or -10 m/s², since gravity acts downward), ...
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