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A ball is dropped from a height of 19.6 ...

A ball is dropped from a height of 19.6 m above the ground. It rebounds from the ground and raises itself up to the same height. Take the starting point as the origin and vertically downward as the positive X-axis. Draw approximate plots of x versus t, v versus t and a versus t. Neglect the small interval during which the ball was in contact with the ground.

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To solve the problem, we will analyze the motion of the ball in two parts: the downward motion (from height to the ground) and the upward motion (from the ground back to the height). We will also derive the necessary equations and sketch the graphs for displacement, velocity, and acceleration. ### Step 1: Analyze the downward motion 1. **Initial Conditions**: - Initial height (h) = 19.6 m - Initial velocity (u) = 0 m/s (the ball is dropped) - Acceleration (a) = 9.8 m/s² (due to gravity, acting downward) ...
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