Home
Class 11
PHYSICS
A man has to go 50 m due north, 40 m due...

A man has to go 50 m due north, 40 m due east and 20 m due south to reach a field, What distance he has to walk to reach the field? b.What is his displacement from his house to the field?

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we need to determine both the total distance traveled by the man and his displacement from his house to the field. ### Step 1: Calculate the Total Distance Traveled 1. The man travels 50 meters due north. 2. He then travels 40 meters due east. 3. Finally, he travels 20 meters due south. **Total Distance = Distance North + Distance East + Distance South** \[ \text{Total Distance} = 50 \, \text{m} + 40 \, \text{m} + 20 \, \text{m} = 110 \, \text{m} \] ### Step 2: Calculate the Displacement Displacement is the shortest straight-line distance from the initial point (his house) to the final point (the field). 1. **Draw a diagram**: Represent the movements on a coordinate system. - Start at point A (the house). - Move to point B (50 m north). - Move to point C (40 m east). - Move to point D (20 m south). 2. **Identify the coordinates**: - Point A (0, 0) - Point B (0, 50) - Point C (40, 50) - Point D (40, 30) (since he moves 20 m south from point B) 3. **Calculate the displacement (AD)**: - The coordinates of point A are (0, 0) and the coordinates of point D are (40, 30). - Use the Pythagorean theorem to find the distance AD: \[ AD = \sqrt{(x_D - x_A)^2 + (y_D - y_A)^2} \] \[ AD = \sqrt{(40 - 0)^2 + (30 - 0)^2} = \sqrt{40^2 + 30^2} \] \[ AD = \sqrt{1600 + 900} = \sqrt{2500} = 50 \, \text{m} \] ### Final Answers - **Total Distance Traveled**: 110 meters - **Displacement**: 50 meters

To solve the problem step by step, we need to determine both the total distance traveled by the man and his displacement from his house to the field. ### Step 1: Calculate the Total Distance Traveled 1. The man travels 50 meters due north. 2. He then travels 40 meters due east. 3. Finally, he travels 20 meters due south. **Total Distance = Distance North + Distance East + Distance South** ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • REST AND MOTION : KINEMATICS

    HC VERMA ENGLISH|Exercise Question for short Answer|13 Videos
  • REST AND MOTION : KINEMATICS

    HC VERMA ENGLISH|Exercise Objective -2|9 Videos
  • PHYSICS AND MATHEMATICS

    HC VERMA ENGLISH|Exercise Question for short Answer|14 Videos
  • ROTATIONAL MECHANICS

    HC VERMA ENGLISH|Exercise Questions for short Answer|21 Videos

Similar Questions

Explore conceptually related problems

A farmer has to go 500 m due north, 400 m due east and 200 m due south to reach his field. If he takes 20 min to reach the field. (a) What distance he has to walk to reach the field ? (b) What is the displacement from his house to the field ? (c) What is the average speed of farmer during the walk ? (d) What is the average velocity of farmer during the walk ?

A man starts from his home and walks 50 m towards, then he turns towards east and walks 40 m and then reaches to his office after moving 20 m towards south. (i) What is the total distance covered by the man from his home to office ? (ii) What is his displacement from his home to office ?

A man goes 10 m due east and than 24 m due north. Find the distance from the starting point.

A man goes 10m due east and then 24 m due north. Find the distance from the starting point.

A man goes 40 m due north and then 50 m due west. Find his distance from the staring point.

A man goes 150 m due east and then 200 m due north. How far is he from the starting point ?

A man goes 40m due north and then 50m due west. Find his distance from the starting point.

A spider crawls 1 m due north , 2 m due east and then climbs 3 m vertically on a wall . What is the magnitude of the resultant dispalcemen ?

A man walks 2 km dur north .After that he walks another 2 km along due West . What is the final displacement from the starting point in each case ?

Two cars A and B are moving due east and due north at 60 km.p.h respetively. At noon A is west of B at a distance 40 km . When are the cars nearest to each other and what is the distance between them then ?