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Two friends A and B are standing a dista...

Two friends A and B are standing a distance x apartin an open field and wind is blowing from A to B.A beats a drum and B hears the sound `t_1` timed after he sees the event. A and B intechange their positions and te experiment is repeated. This time B hears teh drum `t_2` time after he sees the event. Calculte teh velocity of sound in still air v and the velocity of wind u. Neglect the tiem light takes in travelling between the friends.

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To solve the problem, we will analyze the two scenarios described and derive equations based on the information given. ### Step-by-Step Solution: 1. **Understanding the Setup:** - Two friends, A and B, are standing a distance \( x \) apart. - Wind is blowing from A to B. - When A beats the drum, B hears it after a time \( t_1 \). - When A and B switch places, B hears the drum after a time \( t_2 \). 2. **Case 1: A beats the drum, B hears it.** - The sound travels from A to B with the wind. - The effective speed of sound with respect to the ground is \( v + u \) (where \( v \) is the speed of sound in still air and \( u \) is the speed of the wind). - The time taken for sound to travel distance \( x \) is \( t_1 \). - Therefore, we can write the equation: \[ x = (v + u) t_1 \] - Rearranging gives: \[ v + u = \frac{x}{t_1} \quad \text{(Equation 1)} \] 3. **Case 2: B beats the drum, A hears it.** - Now, the sound travels from A to B against the wind. - The effective speed of sound with respect to the ground is \( v - u \). - The time taken for sound to travel distance \( x \) is \( t_2 \). - Therefore, we can write the equation: \[ x = (v - u) t_2 \] - Rearranging gives: \[ v - u = \frac{x}{t_2} \quad \text{(Equation 2)} \] 4. **Adding the Two Equations:** - From Equation 1: \( v + u = \frac{x}{t_1} \) - From Equation 2: \( v - u = \frac{x}{t_2} \) - Adding these two equations: \[ (v + u) + (v - u) = \frac{x}{t_1} + \frac{x}{t_2} \] \[ 2v = \frac{x}{t_1} + \frac{x}{t_2} \] - Thus, we find: \[ v = \frac{x}{2} \left( \frac{1}{t_1} + \frac{1}{t_2} \right) \quad \text{(Equation 3)} \] 5. **Subtracting the Two Equations:** - Now, subtract Equation 2 from Equation 1: \[ (v + u) - (v - u) = \frac{x}{t_1} - \frac{x}{t_2} \] \[ 2u = \frac{x}{t_1} - \frac{x}{t_2} \] - Thus, we find: \[ u = \frac{x}{2} \left( \frac{1}{t_1} - \frac{1}{t_2} \right) \quad \text{(Equation 4)} \] ### Final Results: - The velocity of sound in still air \( v \) is given by: \[ v = \frac{x}{2} \left( \frac{1}{t_1} + \frac{1}{t_2} \right) \] - The velocity of wind \( u \) is given by: \[ u = \frac{x}{2} \left( \frac{1}{t_1} - \frac{1}{t_2} \right) \]

To solve the problem, we will analyze the two scenarios described and derive equations based on the information given. ### Step-by-Step Solution: 1. **Understanding the Setup:** - Two friends, A and B, are standing a distance \( x \) apart. - Wind is blowing from A to B. - When A beats the drum, B hears it after a time \( t_1 \). ...
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