The force on a particle of mass 10 g is `(veci10 + vecj5)N`. If it starts from rest what would be its position at time `t=5s?

Explanation

To solve the problem step by step, we will follow these steps:

### Step 1: Identify the given values
- Mass of the particle, \( m = 10 \, \text{g} = 0.01 \, \text{kg} \)
- Force acting on the particle, \( \vec{F} = (10 \hat{i} + 5 \hat{j}) \, \text{N} \)
- Time, \( t = 5 \, \text{s} \)

### Step 2: Calculate the acceleration in the x-direction
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