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In a TV pictgure tubeelectrons re ejecte...

In a TV pictgure tubeelectrons re ejected from the cathode with negligible speed and reach a velocity of `5x10^6` m/s in travelling one centimeter. Assuming straight line motion, find the constant force exerted on the electron. The mass of the electron is `9.1xx10^-31` kg.

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To find the constant force exerted on the electron in a TV picture tube, we can follow these steps: ### Step 1: Identify the given values - Initial velocity (u) = 0 m/s (since the electrons are ejected with negligible speed) - Final velocity (v) = \(5 \times 10^6\) m/s - Distance (s) = 1 cm = \(1 \times 10^{-2}\) m - Mass of the electron (m) = \(9.1 \times 10^{-31}\) kg ...
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HC VERMA ENGLISH-NEWTON'S LAWS OF MOTION-Exercises
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