Home
Class 11
PHYSICS
In a simple Atwood machine, two unequal ...

In a simple Atwood machine, two unequal masses `m_1 and m_2` are connected by string going over a clamped light smooth pulley . In a typical arrangement `m_1=300g` and `m_2=600g`. The system is released from rest. (a). Find the distance traveled by the first block in the first two seconds. (b). Find the tension in the string. (c). Find the force exerted by the clamp on the pulley.

Text Solution

Verified by Experts

Given that, `vecF=vec(uz)xxvecA and vec(mg)` act on the particle.
For the paeticle to move undeflected with constant velocity net force should be zero.
` :. (vecuxxvecA)+vec(mg)=0`
` or (vecuxxvecA)=-vec(mg)
because ` (vecuxxvecA)` is to the place containing `vecu and vecA, vecu` should be in the xz plane.
Again ` uA sintheta = mg`
` :. u= (mg)/(A sintheta)`
u will be minimum, when `sin theta = 1`,
`rarr theta = 90^0`
`:. u_min = (mg)/A along Z- axis.
Promotional Banner

Topper's Solved these Questions

  • NEWTON'S LAWS OF MOTION

    HC VERMA ENGLISH|Exercise Questions for short Answer|17 Videos
  • NEWTON'S LAWS OF MOTION

    HC VERMA ENGLISH|Exercise Objective -2|9 Videos
  • LAWS OF THERMODYNAMICS

    HC VERMA ENGLISH|Exercise All Questions|64 Videos
  • PHYSICS AND MATHEMATICS

    HC VERMA ENGLISH|Exercise Question for short Answer|14 Videos

Similar Questions

Explore conceptually related problems

In a simple Atwood machine, two unequal masses m_1 and m_2 are connected by string going over a clamped light smooth pulley . In a typical arrangement m_1=300g and m_2=600g . The system is released from rest. (a) Find the distance travelled by the first block in first two seconds. (b) Find the tension in the string. (c) Find the force exerted by clamp on the pulley.

Two unequal masses are connected by a very light string over a clamped light smooth pulley. Find the acceleration of the system and the tension in the string.

Two unequal masses of 1kg and 2kg are connected by a string going over a clamed light smooth pulley as shown in figure . The system is released from rest .The larger mass is stopped for a moment 1.0 s after the system is set in motion.Find the time elapsed before the string is tight again.

In a simple Atwood's machine, two unequal masses m_1= 5 kg , m_2 = 2 kg are connected by a string going over a clamped light smooth pulley. Now a constant force F = 1 N is applied on each mass in vertically downward direction. The ratio of acceleration of either block before and after applying the force will be

Two bodies of masses 1 kg and 2 kg are connected by a very light string passed over a clamped light smooth pulley. If the system is released from rest, find the acceleration of the two masses and the tension in the string

Two bodies of masses m_1 and m_2 are connected by a light string going over a smooth lilght pulley at the end of an incline. The mass_1 lies on the incline m_2 hangs vertically. The system is t rest. Find the angle of the incline and the fore exerted by the incline on the body of mass m_1.

Two unequal masses of 1 kg and 2 kg are attached at the two ends of a light inextensible string passing over a smooth pulley as shown . If the system is released from rest, find the work done by string on both the blocks in 1 s. (Take g= 10 m//s^2 ).

Two unequal masses of 1 kg and 2 kg are attached at the two ends of a light inextensible string passing over a smooth pulley as shown in figure. If the system is released from rest, find the work done by string on both the blocks in 1 s. (Take g = 10 ms^(-2) )

The pulley is light and smooth : the strings are inextensible and light. The system is released from rest, find the acceleration of each block, tensions in the strings and reaction in pulley.

In the situation shown in figure, both the pulleys and the strings are light and all the surfaces are frictionless. The acceleration of mass M, tension in the string PQ and force exerted by the clamp on the pulley, will respectively be -

HC VERMA ENGLISH-NEWTON'S LAWS OF MOTION-Exercises
  1. An empty plastic box of mass m is found to accelerate up at the rate o...

    Text Solution

    |

  2. A force vecF=vecvxxvecA is exerted on a particle in addition to the fo...

    Text Solution

    |

  3. In a simple Atwood machine, two unequal masses m1 and m2 are connected...

    Text Solution

    |

  4. In a simple Atwood machine, two unequal masses m1 and m2 are connected...

    Text Solution

    |

  5. Figure shows a uniform rod of length 30 cm having a mass of 3.0 kg. Th...

    Text Solution

    |

  6. Three blocks of masses m1, m2 and m3 are connected as shown in the fig...

    Text Solution

    |

  7. A constant force F=m2g/s is applied on the block of mass m1 as shown i...

    Text Solution

    |

  8. In figure m1=5 kg, m2=2kg and F=1N. Find the acceleration of either bl...

    Text Solution

    |

  9. Let m1=1 kg, m2=2kg and m3=3kg is figure. Find the acceleration of m1,...

    Text Solution

    |

  10. In the previous problem, suppose m2=2.0kg and m3=3.0 kg. What should b...

    Text Solution

    |

  11. Calculate the tension in the string shown in figure. The pulley and th...

    Text Solution

    |

  12. Consider4 the situation shown in figure. Bothe the pulleys and the str...

    Text Solution

    |

  13. find the acceleration of the block of mass M in the situation shown in...

    Text Solution

    |

  14. In figure m(1)= 1 kg and m(2)= 4 kg Find the mass m of the hanging blo...

    Text Solution

    |

  15. Find the acceleration of the blocks A and B in the this situations sho...

    Text Solution

    |

  16. Find the acceleration of the 500 g block in figure.

    Text Solution

    |

  17. A monkey a mass 15 kg is climbing on a rope with one end fixed to the ...

    Text Solution

    |

  18. A Monkey is Climbing on a Rope that Goes Over a Smooth Light Pulley an...

    Text Solution

    |

  19. A string is wrapped on a wheel of moment of inertia 0.20 kg-m^2 and ra...

    Text Solution

    |

  20. A monkey A (mass = 5 kg) is climbing up a rope tied to a rigid support...

    Text Solution

    |