An elevator weighing 500 kg is to be lifted up at a constant velociy of 0.20 m/s. What would be the minimum horsepower of the motor to be used?

Explanation

To solve the problem of determining the minimum horsepower of the motor required to lift an elevator weighing 500 kg at a constant velocity of 0.20 m/s, we can follow these steps:

### Step 1: Calculate the Weight of the Elevator
The weight (force due to gravity) of the elevator can be calculated using the formula:
\[ \text{Weight} (W) = m \cdot g \]
where:
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