A constant force of 2.50 N accelerates a stationary particle of mass 15 g through a displacement of 2.50 m. Find the work done and the average power delivered.

Answer

A, B, C

Explanation

`F=2.50N, S=2.5m, m=15g`
`=0.015kg`
So, `w=F.S`
a=F/m=2.5/0.015`
`500/3 m/s^2=F.S cos0^0`
(acing along the same line)
`=2.5xx2.5=6.25J`
Let the veolocity of the body at B=v
Applyng work energy principle,
`1/2 mv^2-0=6.25`
`rarr v=sqrt9(6.25xx2)/0.15)=28.86 m/sec`
So, time taken to travel from A to B,
`t=(v-u)/a =((28.86)xx3)/500`
`:.` Average powere `=W/t`
`=(6.25xx500)/((28.86)xx3)=36.1W`