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A man moves on a straight horizontal ro...

A man moves on a straight horizontal road with a block of mass 2 kg in his hand. If he covers a distance of 340 m with an acceleration of `0.5 m/s^2` find the work done by the man on the block during the motion.

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To solve the problem, we need to calculate the work done by the man on the block while he moves a distance of 340 meters with an acceleration of 0.5 m/s². Here's a step-by-step solution: ### Step 1: Identify the given values - Mass of the block (m) = 2 kg - Distance covered (s) = 340 m - Acceleration (a) = 0.5 m/s² ### Step 2: Calculate the force exerted by the man on the block Using Newton's second law of motion, we can calculate the force (F) exerted on the block: \[ F = m \cdot a \] Substituting the known values: \[ F = 2 \, \text{kg} \cdot 0.5 \, \text{m/s}^2 = 1 \, \text{N} \] ### Step 3: Calculate the work done by the man on the block The work done (W) is given by the formula: \[ W = F \cdot s \] Substituting the values of force and distance: \[ W = 1 \, \text{N} \cdot 340 \, \text{m} = 340 \, \text{J} \] ### Final Answer: The work done by the man on the block during the motion is **340 Joules**. ---

To solve the problem, we need to calculate the work done by the man on the block while he moves a distance of 340 meters with an acceleration of 0.5 m/s². Here's a step-by-step solution: ### Step 1: Identify the given values - Mass of the block (m) = 2 kg - Distance covered (s) = 340 m - Acceleration (a) = 0.5 m/s² ### Step 2: Calculate the force exerted by the man on the block ...
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HC VERMA ENGLISH-WORK AND ENERGY-Exercises
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  2. A particle moves rom a point vecr1=(2m)veci+(3m)vecj to another point ...

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  13. A block of mass 2.0 kg is pushed down an inclined plane of inclination...

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  14. A 250 g block slides on aeroug horizontal table. Find the work donen b...

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