A block of mass m sliding n a smooth horizontal surface with velocity `vecv` meets a long horizontal spring fixed ast one end and having spring constant k as shown n figure. Find the maximum compression of the spring. Will the velocity of the block be the same as v whenit comes back to the original position shown?

Explanation

Let the compreshension be x
a. According to law of conservation of energy
`1/2 mv^2=1/2 kx^2`
`rarr x^2=(mv^2)/k`
`x=v sqrt((m/k))`
b.
No. It will be in the opposite direction and magnitude will be less due to loss in spring.