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The centre of mass of a system of partic...

The centre of mass of a system of particles is at the origin. It follows that:

A

the number of particle to the righ of the origin is equal to the number of particles to the left

B

the total mass of the particles to the right of the origin is same as the total mass to the left of theorigin

C

the number of particles on X-axis should be equal to the number of particles on Y-axis

D

if there is a particle on the positive X-axis, there must be at least one particle on the negative X-axis.

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At one instant, the centre of mass of a system of two particles is located on the x-axis at x=3.0m and has a velocity of (6.0m//s)hatj . One of the particles is at the origin, the other particle has a mass of 0.10kg and is at rest on the x- axis at x=12.0m . (a) What is the mass of the particle at the origin? (b) Calculate the total momentum of this system. (c) What is the velocity of the particle at the origin?

The center of mass of a system of two particles divides the distance between them.

Knowledge Check

  • The centre of mass of a system of two particle of masses m_1 and m_2 is at a distance d_1 from mass m_1 and at a distance d_2 from mass m_2 such that.

    A
    `d_1/d_2 = m_2/m_1`
    B
    `d_1/d_2 = m_1/m_2`
    C
    `d_1/d_2 = m_1/m_1 + m_2`
    D
    `d_1/d_2 = m_2/m_1 + m_2`

  • Centre of mass of three particles of masses 1 kg, 2 kg and 3 kg lies at the point (1,2,3) and centre of mass of another system of particles 3 kg and 2 kg lies at the point (-1, 3, -2) . Where should we put a particle of mass 5 kg so that the centre of mass of entire system lies at the centre of mass of first system ?

    A
    (0, 0, 0)
    B
    (1, 3, 2)
    C
    (-1, 2, 3)
    D
    (3, 1, 8)

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