A wheel rotating at an angular speed of 20 rad/s is brought to rest by a constant torque in 4.0 seconds. If the moment of inertia of the wheel about the axis of rotation is 0.20 `kg-m^2` find the work done by the torque in the first two seconds.

Explanation

To solve the problem step by step, we will follow the outlined process to find the work done by the torque in the first two seconds.

### Step 1: Identify the given values
- Initial angular speed, \( \omega_0 = 20 \, \text{rad/s} \)
- Final angular speed, \( \omega_f = 0 \, \text{rad/s} \) (since the wheel comes to rest)
- Time taken to come to rest, \( t = 4 \, \text{s} \)
- Moment of inertia, \( I = 0.20 \, \text{kg m}^2 \)

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