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A circular disc A of radius r is made fr...

A circular disc A of radius r is made from an iron plate of thickness t and another circular disc B of radius 4r is made from an iron plate of thickness t/4. The relation between the moments of inertia `I_A and I_B` is

A

`I_AgtI_B`

B

`I_A=I_B`

C

`I_AltI_B`

D

depends on the actual values of t and r

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The correct Answer is:
To find the relation between the moments of inertia \( I_A \) and \( I_B \) for the two circular discs, we will follow these steps: ### Step 1: Calculate the Mass of Disc A The mass \( m_A \) of disc A can be calculated using the formula: \[ m_A = \text{Density} \times \text{Volume} \] The volume \( V_A \) of disc A is given by: \[ V_A = \text{Area} \times \text{Thickness} = \pi r^2 \times t \] Thus, the mass of disc A is: \[ m_A = \rho \times V_A = \rho \times \pi r^2 t \] ### Step 2: Calculate the Moment of Inertia of Disc A The moment of inertia \( I_A \) for a circular disc is given by: \[ I_A = \frac{1}{2} m_A r^2 \] Substituting the expression for \( m_A \): \[ I_A = \frac{1}{2} \left( \rho \pi r^2 t \right) r^2 = \frac{1}{2} \rho \pi t r^4 \] ### Step 3: Calculate the Mass of Disc B For disc B, the radius is \( 4r \) and the thickness is \( \frac{t}{4} \). The volume \( V_B \) of disc B is: \[ V_B = \pi (4r)^2 \times \frac{t}{4} = \pi \times 16r^2 \times \frac{t}{4} = 4 \pi r^2 t \] Thus, the mass of disc B is: \[ m_B = \rho \times V_B = \rho \times 4 \pi r^2 t \] ### Step 4: Calculate the Moment of Inertia of Disc B The moment of inertia \( I_B \) for disc B is: \[ I_B = \frac{1}{2} m_B (4r)^2 \] Substituting the expression for \( m_B \): \[ I_B = \frac{1}{2} \left( \rho \times 4 \pi r^2 t \right) (16r^2) = \frac{1}{2} \times 4 \times 16 \rho \pi r^2 t \times r^2 = 32 \rho \pi t r^4 \] ### Step 5: Compare the Moments of Inertia Now we have: \[ I_A = \frac{1}{2} \rho \pi t r^4 \] \[ I_B = 32 \rho \pi t r^4 \] To compare \( I_A \) and \( I_B \): \[ I_B = 64 I_A \] Thus, we find that: \[ I_A < I_B \] ### Conclusion The relation between the moments of inertia \( I_A \) and \( I_B \) is: \[ I_A < I_B \]
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HC VERMA ENGLISH-ROTATIONAL MECHANICS-Objective -1
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  5. A circular disc A of radius r is made from an iron plate of thickness ...

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  6. Equal torques asct on the discs A and B of theh previous problem, init...

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  8. The moment of inertia of a uniform semicircular wire of mass 'M' and r...

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  9. Let I1 and I2 be the moments of inertia of two bodies of identical ge...

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